2x^2-21x+27=(2x-3)(x-9)

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Solution for 2x^2-21x+27=(2x-3)(x-9) equation: 



2x^2-21x+27=(2x-3)(x-9)

We move all terms to the left:

2x^2-21x+27-((2x-3)(x-9))=0

We multiply parentheses ..

2x^2-((+2x^2-18x-3x+27))-21x+27=0



We calculate terms in parentheses: -((+2x^2-18x-3x+27)), so:

(+2x^2-18x-3x+27)

We get rid of parentheses

2x^2-18x-3x+27

We add all the numbers together, and all the variables

2x^2-21x+27

Back to the equation:

-(2x^2-21x+27)



We add all the numbers together, and all the variables

2x^2-21x-(2x^2-21x+27)+27=0

We get rid of parentheses

2x^2-2x^2-21x+21x-27+27=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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